Base | Representation |
---|---|
bin | 1101000010110001001100… |
… | …0001101100100010001010 |
3 | 1212210000011221011120111200 |
4 | 3100230103001230202022 |
5 | 3334431302020404002 |
6 | 50300132505005030 |
7 | 3010055451200613 |
oct | 320542301544212 |
9 | 55700157146450 |
10 | 14341215013002 |
11 | 462a0910001a9 |
12 | 173750ba83776 |
13 | 8004a8784ac7 |
14 | 378193298c0a |
15 | 19d0aba97b1c |
hex | d0b1306c88a |
14341215013002 has 48 divisors (see below), whose sum is σ = 32721796311360. Its totient is φ = 4526899223616.
The previous prime is 14341215012961. The next prime is 14341215013003. The reversal of 14341215013002 is 20031051214341.
14341215013002 is a `hidden beast` number, since 1 + 4 + 3 + 4 + 121 + 501 + 30 + 0 + 2 = 666.
It is not an unprimeable number, because it can be changed into a prime (14341215013003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8007718 + ... + 9633585.
It is an arithmetic number, because the mean of its divisors is an integer number (681704089820).
Almost surely, 214341215013002 is an apocalyptic number.
14341215013002 is an abundant number, since it is smaller than the sum of its proper divisors (18380581298358).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14341215013002 is a wasteful number, since it uses less digits than its factorization.
14341215013002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17643707 (or 17643704 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 27.
Adding to 14341215013002 its reverse (20031051214341), we get a palindrome (34372266227343).
The spelling of 14341215013002 in words is "fourteen trillion, three hundred forty-one billion, two hundred fifteen million, thirteen thousand, two".
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