143412433 has 2 divisors, whose sum is σ = 143412434. Its totient is φ = 143412432.

The previous prime is 143412397. The next prime is 143412443. The reversal of 143412433 is 334214341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 91240704 + 52171729 = 9552^2 + 7223^2 .

It is a cyclic number.

It is not a de Polignac number, because 143412433 - 2¹⁷ = 143281361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143412398 and 143412407.

It is not a weakly prime, because it can be changed into another prime (143412443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71706216 + 71706217.

It is an arithmetic number, because the mean of its divisors is an integer number (71706217).

Almost surely, 2^143412433 is an apocalyptic number.

It is an amenable number.

143412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

143412433 is an equidigital number, since it uses as much as digits as its factorization.

143412433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3456, while the sum is 25.

The square root of 143412433 is about 11975.4930169910. The cubic root of 143412433 is about 523.4344083334.

Adding to 143412433 its reverse (334214341), we get a palindrome (477626774).

The spelling of 143412433 in words is "one hundred forty-three million, four hundred twelve thousand, four hundred thirty-three".