Base | Representation |
---|---|
bin | 1000010110010000011… |
… | …0101101101101001001 |
3 | 111201011201121200121211 |
4 | 2011210012231231021 |
5 | 4322202312334231 |
6 | 145514434533121 |
7 | 13234626543631 |
oct | 2054406555511 |
9 | 451151550554 |
10 | 143413402441 |
11 | 559041439a1 |
12 | 23964a371a1 |
13 | 106a6acb25a |
14 | 6d26ac76c1 |
15 | 3ae5724eb1 |
hex | 21641adb49 |
143413402441 has 4 divisors (see below), whose sum is σ = 143504691984. Its totient is φ = 143322112900.
The previous prime is 143413402423. The next prime is 143413402487. The reversal of 143413402441 is 144204314341.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 143413402441 - 213 = 143413394249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143413402421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45642415 + ... + 45645556.
It is an arithmetic number, because the mean of its divisors is an integer number (35876172996).
Almost surely, 2143413402441 is an apocalyptic number.
It is an amenable number.
143413402441 is a deficient number, since it is larger than the sum of its proper divisors (91289543).
143413402441 is an equidigital number, since it uses as much as digits as its factorization.
143413402441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91289542.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 143413402441 its reverse (144204314341), we get a palindrome (287617716782).
The spelling of 143413402441 in words is "one hundred forty-three billion, four hundred thirteen million, four hundred two thousand, four hundred forty-one".
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