Base | Representation |
---|---|
bin | 11010101101101000… |
… | …00110011000101111 |
3 | 1101000110212121111002 |
4 | 31112310012120233 |
5 | 213332344300421 |
6 | 10331025550515 |
7 | 1015251614063 |
oct | 152664063057 |
9 | 41013777432 |
10 | 14341400111 |
11 | 609a38a195 |
12 | 2942aa543b |
13 | 147727388c |
14 | 9a0985aa3 |
15 | 58e0bdb0b |
hex | 356d0662f |
14341400111 has 2 divisors, whose sum is σ = 14341400112. Its totient is φ = 14341400110.
The previous prime is 14341400083. The next prime is 14341400149. The reversal of 14341400111 is 11100414341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14341400111 - 222 = 14337205807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14341400911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170700055 + 7170700056.
It is an arithmetic number, because the mean of its divisors is an integer number (7170700056).
Almost surely, 214341400111 is an apocalyptic number.
14341400111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14341400111 is an equidigital number, since it uses as much as digits as its factorization.
14341400111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 14341400111 its reverse (11100414341), we get a palindrome (25441814452).
The spelling of 14341400111 in words is "fourteen billion, three hundred forty-one million, four hundred thousand, one hundred eleven".
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