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143414103034113 = 3172812041235963
BaseRepresentation
bin100000100110111100110010…
…101010101100100100000001
3200210210020212102102112211220
4200212330302222230210001
5122244144040334042423
61225003310203425253
742131220111202542
oct4046746252544401
9623706772375756
10143414103034113
114177264140160a
1214102744b25229
136203b79624322
14275b3cb4004c9
15118a7e38109e3
hex826f32aac901

143414103034113 has 8 divisors (see below), whose sum is σ = 202466968989408. Its totient is φ = 89985319550784.

The previous prime is 143414103034087. The next prime is 143414103034183. The reversal of 143414103034113 is 311430301414341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 143414103034113 - 212 = 143414103030017 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (143414103034183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1406020617931 + ... + 1406020618032.

It is an arithmetic number, because the mean of its divisors is an integer number (25308371123676).

Almost surely, 2143414103034113 is an apocalyptic number.

It is an amenable number.

143414103034113 is a deficient number, since it is larger than the sum of its proper divisors (59052865955295).

143414103034113 is a wasteful number, since it uses less digits than its factorization.

143414103034113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2812041235983.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 143414103034113 its reverse (311430301414341), we get a palindrome (454844404448454).

The spelling of 143414103034113 in words is "one hundred forty-three trillion, four hundred fourteen billion, one hundred three million, thirty-four thousand, one hundred thirteen".

Divisors: 1 3 17 51 2812041235963 8436123707889 47804701011371 143414103034113