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14341431441 = 34780477147
BaseRepresentation
bin11010101101101000…
…01110000010010001
31101000110221012110110
431112310032002101
5213332401301231
610331030351533
71015252104321
oct152664160221
941013835413
1014341431441
11609a400787
122942abb5a9
131477284c0c
149a0993281
1558e0c8046
hex356d0e091

14341431441 has 4 divisors (see below), whose sum is σ = 19121908592. Its totient is φ = 9560954292.

The previous prime is 14341431409. The next prime is 14341431457. The reversal of 14341431441 is 14413414341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14341431441 - 25 = 14341431409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14341431399 and 14341431408.

It is not an unprimeable number, because it can be changed into a prime (14341431241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2390238571 + ... + 2390238576.

It is an arithmetic number, because the mean of its divisors is an integer number (4780477148).

Almost surely, 214341431441 is an apocalyptic number.

It is an amenable number.

14341431441 is a deficient number, since it is larger than the sum of its proper divisors (4780477151).

14341431441 is an equidigital number, since it uses as much as digits as its factorization.

14341431441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4780477150.

The product of its digits is 9216, while the sum is 30.

Adding to 14341431441 its reverse (14413414341), we get a palindrome (28754845782).

The spelling of 14341431441 in words is "fourteen billion, three hundred forty-one million, four hundred thirty-one thousand, four hundred forty-one".

Divisors: 1 3 4780477147 14341431441