Base | Representation |
---|---|
bin | 10100110111101110010… |
… | …101001100000010010111 |
3 | 12002002222102221002202022 |
4 | 110313232111030002113 |
5 | 141444241444010203 |
6 | 3014512304403355 |
7 | 205422242206334 |
oct | 24675625140227 |
9 | 5062872832668 |
10 | 1434222641303 |
11 | 503283322221 |
12 | 1b1b6631655b |
13 | a5328a7439a |
14 | 4d5b97a198b |
15 | 2749283ba38 |
hex | 14dee54c097 |
1434222641303 has 4 divisors (see below), whose sum is σ = 1435447426968. Its totient is φ = 1432997855640.
The previous prime is 1434222641279. The next prime is 1434222641311. The reversal of 1434222641303 is 3031462224341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1434222641303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1434222641003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 612391076 + ... + 612393417.
It is an arithmetic number, because the mean of its divisors is an integer number (358861856742).
Almost surely, 21434222641303 is an apocalyptic number.
1434222641303 is a deficient number, since it is larger than the sum of its proper divisors (1224785665).
1434222641303 is a wasteful number, since it uses less digits than its factorization.
1434222641303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1224785664.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 1434222641303 its reverse (3031462224341), we get a palindrome (4465684865644).
The spelling of 1434222641303 in words is "one trillion, four hundred thirty-four billion, two hundred twenty-two million, six hundred forty-one thousand, three hundred three".
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