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14342444401 is a prime number
BaseRepresentation
bin11010101101110000…
…00101010101110001
31101000112211122222111
431112320011111301
5213333131210101
610331104205321
71015263523465
oct152670052561
941015748874
1014342444401
11609aa3283a
122943309841
13147754acbc
149a0b784a5
1558e228251
hex356e05571

14342444401 has 2 divisors, whose sum is σ = 14342444402. Its totient is φ = 14342444400.

The previous prime is 14342444387. The next prime is 14342444411. The reversal of 14342444401 is 10444424341.

14342444401 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13863885025 + 478559376 = 117745^2 + 21876^2 .

It is a cyclic number.

It is not a de Polignac number, because 14342444401 - 217 = 14342313329 is a prime.

It is a super-2 number, since 2×143424444012 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14342444411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171222200 + 7171222201.

It is an arithmetic number, because the mean of its divisors is an integer number (7171222201).

Almost surely, 214342444401 is an apocalyptic number.

It is an amenable number.

14342444401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14342444401 is an equidigital number, since it uses as much as digits as its factorization.

14342444401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 31.

Adding to 14342444401 its reverse (10444424341), we get a palindrome (24786868742).

The spelling of 14342444401 in words is "fourteen billion, three hundred forty-two million, four hundred forty-four thousand, four hundred one".