Base | Representation |
---|---|
bin | 10100110111101111110… |
… | …011111111100111110101 |
3 | 12002010001011200202102111 |
4 | 110313233303333213311 |
5 | 141444314324303013 |
6 | 3014514553211021 |
7 | 205422663356506 |
oct | 24675763774765 |
9 | 5063034622374 |
10 | 1434247494133 |
11 | 503296357553 |
12 | 1b1b72700a71 |
13 | a5330c665bc |
14 | 4d5bcbd0bad |
15 | 27494aea73d |
hex | 14defcff9f5 |
1434247494133 has 2 divisors, whose sum is σ = 1434247494134. Its totient is φ = 1434247494132.
The previous prime is 1434247494059. The next prime is 1434247494167. The reversal of 1434247494133 is 3314947424341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 743392288804 + 690855205329 = 862202^2 + 831177^2 .
It is a cyclic number.
It is not a de Polignac number, because 1434247494133 - 29 = 1434247493621 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1434257494133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717123747066 + 717123747067.
It is an arithmetic number, because the mean of its divisors is an integer number (717123747067).
Almost surely, 21434247494133 is an apocalyptic number.
It is an amenable number.
1434247494133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434247494133 is an equidigital number, since it uses as much as digits as its factorization.
1434247494133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3483648, while the sum is 49.
The spelling of 1434247494133 in words is "one trillion, four hundred thirty-four billion, two hundred forty-seven million, four hundred ninety-four thousand, one hundred thirty-three".
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