Base | Representation |
---|---|
bin | 1101000010111000001110… |
… | …0001101100111000000111 |
3 | 1212210012001110201100222101 |
4 | 3100232003201230320013 |
5 | 3334444133211414312 |
6 | 50301044051212531 |
7 | 3010153310151115 |
oct | 320560341547007 |
9 | 55705043640871 |
10 | 14343102451207 |
11 | 462a96a456492 |
12 | 1737957ba7147 |
13 | 80071980aa4a |
14 | 3782d1c12ab5 |
15 | 19d16c623a57 |
hex | d0b8386ce07 |
14343102451207 has 2 divisors, whose sum is σ = 14343102451208. Its totient is φ = 14343102451206.
The previous prime is 14343102451193. The next prime is 14343102451229. The reversal of 14343102451207 is 70215420134341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14343102451207 - 235 = 14308742712839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14343102451277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171551225603 + 7171551225604.
It is an arithmetic number, because the mean of its divisors is an integer number (7171551225604).
Almost surely, 214343102451207 is an apocalyptic number.
14343102451207 is a deficient number, since it is larger than the sum of its proper divisors (1).
14343102451207 is an equidigital number, since it uses as much as digits as its factorization.
14343102451207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 37.
Adding to 14343102451207 its reverse (70215420134341), we get a palindrome (84558522585548).
The spelling of 14343102451207 in words is "fourteen trillion, three hundred forty-three billion, one hundred two million, four hundred fifty-one thousand, two hundred seven".
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