Base | Representation |
---|---|
bin | 1000010110010100100… |
… | …1111111110001111101 |
3 | 111201012221210202222101 |
4 | 2011211021333301331 |
5 | 4322221321241000 |
6 | 145520304545101 |
7 | 13235232503512 |
oct | 2054511776175 |
9 | 451187722871 |
10 | 143431040125 |
11 | 559130a039a |
12 | 2396a922191 |
13 | 106aa665359 |
14 | 6d29199309 |
15 | 3ae705ae6a |
hex | 216527fc7d |
143431040125 has 16 divisors (see below), whose sum is σ = 179750937600. Its totient is φ = 114264704400.
The previous prime is 143431040111. The next prime is 143431040141. The reversal of 143431040125 is 521040134341.
It is not a de Polignac number, because 143431040125 - 211 = 143431038077 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143431040093 and 143431040102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2370645 + ... + 2430394.
It is an arithmetic number, because the mean of its divisors is an integer number (11234433600).
Almost surely, 2143431040125 is an apocalyptic number.
It is an amenable number.
143431040125 is a deficient number, since it is larger than the sum of its proper divisors (36319897475).
143431040125 is an equidigital number, since it uses as much as digits as its factorization.
143431040125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4801293 (or 4801283 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 143431040125 its reverse (521040134341), we get a palindrome (664471174466).
The spelling of 143431040125 in words is "one hundred forty-three billion, four hundred thirty-one million, forty thousand, one hundred twenty-five".
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