Base | Representation |
---|---|
bin | 1101000010111000010101… |
… | …1011000000110111010101 |
3 | 1212210012010200120001011002 |
4 | 3100232011123000313111 |
5 | 3334444214332040001 |
6 | 50301051144553045 |
7 | 3010154144361215 |
oct | 320560533006725 |
9 | 55705120501132 |
10 | 14343134252501 |
11 | 462a9863a724a |
12 | 1737966782785 |
13 | 800723293892 |
14 | 3782d6130245 |
15 | 19d17030646b |
hex | d0b856c0dd5 |
14343134252501 has 2 divisors, whose sum is σ = 14343134252502. Its totient is φ = 14343134252500.
The previous prime is 14343134252431. The next prime is 14343134252507. The reversal of 14343134252501 is 10525243134341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12944056906225 + 1399077346276 = 3597785^2 + 1182826^2 .
It is a cyclic number.
It is not a de Polignac number, because 14343134252501 - 218 = 14343133990357 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14343134252507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171567126250 + 7171567126251.
It is an arithmetic number, because the mean of its divisors is an integer number (7171567126251).
Almost surely, 214343134252501 is an apocalyptic number.
It is an amenable number.
14343134252501 is a deficient number, since it is larger than the sum of its proper divisors (1).
14343134252501 is an equidigital number, since it uses as much as digits as its factorization.
14343134252501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 38.
Adding to 14343134252501 its reverse (10525243134341), we get a palindrome (24868377386842).
The spelling of 14343134252501 in words is "fourteen trillion, three hundred forty-three billion, one hundred thirty-four million, two hundred fifty-two thousand, five hundred one".
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