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14343233201 = 111303930291
BaseRepresentation
bin11010101101110110…
…00101111010110001
31101000121022202000022
431112323011322301
5213333331430301
610331133133225
71015303320263
oct152673057261
941017282008
1014343233201
1160a0421440
12294362a215
13147776604b
149a0d01b33
1558e331d1b
hex356ec5eb1

14343233201 has 4 divisors (see below), whose sum is σ = 15647163504. Its totient is φ = 13039302900.

The previous prime is 14343233189. The next prime is 14343233287. The reversal of 14343233201 is 10233234341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14343233201 - 214 = 14343216817 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14343233501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 651965135 + ... + 651965156.

It is an arithmetic number, because the mean of its divisors is an integer number (3911790876).

Almost surely, 214343233201 is an apocalyptic number.

14343233201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14343233201 is a deficient number, since it is larger than the sum of its proper divisors (1303930303).

14343233201 is a wasteful number, since it uses less digits than its factorization.

14343233201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1303930302.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 14343233201 its reverse (10233234341), we get a palindrome (24576467542).

The spelling of 14343233201 in words is "fourteen billion, three hundred forty-three million, two hundred thirty-three thousand, two hundred one".

Divisors: 1 11 1303930291 14343233201