Base | Representation |
---|---|
bin | 1101000010111000111111… |
… | …1110100001101110100111 |
3 | 1212210012121000202201201122 |
4 | 3100232033332201232213 |
5 | 3340000100200144221 |
6 | 50301120512244155 |
7 | 3010161424503551 |
oct | 320561776415647 |
9 | 55705530681648 |
10 | 14343311334311 |
11 | 462aa67356453 |
12 | 17379b5b4065b |
13 | 800750b8540b |
14 | 3783118684d1 |
15 | 19d180b34eab |
hex | d0b8ffa1ba7 |
14343311334311 has 2 divisors, whose sum is σ = 14343311334312. Its totient is φ = 14343311334310.
The previous prime is 14343311334277. The next prime is 14343311334377. The reversal of 14343311334311 is 11343311334341.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14343311334311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14343311324311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171655667155 + 7171655667156.
It is an arithmetic number, because the mean of its divisors is an integer number (7171655667156).
Almost surely, 214343311334311 is an apocalyptic number.
14343311334311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14343311334311 is an equidigital number, since it uses as much as digits as its factorization.
14343311334311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46656, while the sum is 35.
Adding to 14343311334311 its reverse (11343311334341), we get a palindrome (25686622668652).
The spelling of 14343311334311 in words is "fourteen trillion, three hundred forty-three billion, three hundred eleven million, three hundred thirty-four thousand, three hundred eleven".
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