1434342011 has 2 divisors, whose sum is σ = 1434342012. Its totient is φ = 1434342010.

The previous prime is 1434341989. The next prime is 1434342017. The reversal of 1434342011 is 1102434341.

It is a strong prime.

It is an emirp because it is prime and its reverse (1102434341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1434342011 - 2¹⁰ = 1434340987 is a prime.

It is not a weakly prime, because it can be changed into another prime (1434342017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717171005 + 717171006.

It is an arithmetic number, because the mean of its divisors is an integer number (717171006).

Almost surely, 2^1434342011 is an apocalyptic number.

1434342011 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434342011 is an equidigital number, since it uses as much as digits as its factorization.

1434342011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 1434342011 is about 37872.7079966564. The cubic root of 1434342011 is about 1127.7623012694.

Adding to 1434342011 its reverse (1102434341), we get a palindrome (2536776352).

The spelling of 1434342011 in words is "one billion, four hundred thirty-four million, three hundred forty-two thousand, eleven".