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143434234412000 = 255376183977889
BaseRepresentation
bin100000100111001111100010…
…100101110011101111100000
3200210212011211102011111200022
4200213033202211303233200
5122300011303002141000
61225020435545013012
742132532020116420
oct4047174245635740
9623764742144608
10143434234412000
11417801320037a4
1214106622a84168
136205a372aa94c
14275c37ad24480
15118b0c0d7d585
hex8273e2973be0

143434234412000 has 192 divisors, whose sum is σ = 409366012648320. Its totient is φ = 48371263488000.

The previous prime is 143434234411997. The next prime is 143434234412003. The reversal of 143434234412000 is 214432434341.

143434234412000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (143434234411997) and next prime (143434234412003).

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143434234412003) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 40280945 + ... + 43696944.

It is an arithmetic number, because the mean of its divisors is an integer number (2132114649210).

Almost surely, 2143434234412000 is an apocalyptic number.

143434234412000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

143434234412000 is an abundant number, since it is smaller than the sum of its proper divisors (265931778236320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

143434234412000 is an equidigital number, since it uses as much as digits as its factorization.

143434234412000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83977982 (or 83977964 counting only the distinct ones).

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 143434234412000 its reverse (214432434341), we get a palindrome (143648666846341).

The spelling of 143434234412000 in words is "one hundred forty-three trillion, four hundred thirty-four billion, two hundred thirty-four million, four hundred twelve thousand".