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143436465013 is a prime number
BaseRepresentation
bin1000010110010101111…
…0101100001101110101
3111201020100000101112011
42011211132230031311
54322224213340023
6145521021124221
713235326556512
oct2054536541565
9451210011464
10143436465013
1155916166176
12239706b9671
13106ab81464a
146d29bac309
153ae777d50d
hex21657ac375

143436465013 has 2 divisors, whose sum is σ = 143436465014. Its totient is φ = 143436465012.

The previous prime is 143436464981. The next prime is 143436465031. The reversal of 143436465013 is 310564634341.

Together with next prime (143436465031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121411827364 + 22024637649 = 348442^2 + 148407^2 .

It is a cyclic number.

It is not a de Polignac number, because 143436465013 - 25 = 143436464981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143436468013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71718232506 + 71718232507.

It is an arithmetic number, because the mean of its divisors is an integer number (71718232507).

Almost surely, 2143436465013 is an apocalyptic number.

It is an amenable number.

143436465013 is a deficient number, since it is larger than the sum of its proper divisors (1).

143436465013 is an equidigital number, since it uses as much as digits as its factorization.

143436465013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 40.

The spelling of 143436465013 in words is "one hundred forty-three billion, four hundred thirty-six million, four hundred sixty-five thousand, thirteen".