1434402212101 has 4 divisors (see below), whose sum is σ = 1442991447072. Its totient is φ = 1425812977132.

The previous prime is 1434402212081. The next prime is 1434402212153. The reversal of 1434402212101 is 1012122044341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1434402212101 - 2⁷ = 1434402211973 is a prime.

It is a super-3 number, since 3×1434402212101³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1434402212401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4294617235 + ... + 4294617568.

It is an arithmetic number, because the mean of its divisors is an integer number (360747861768).

Almost surely, 2^{1434402212101} is an apocalyptic number.

It is an amenable number.

1434402212101 is a deficient number, since it is larger than the sum of its proper divisors (8589234971).

1434402212101 is an equidigital number, since it uses as much as digits as its factorization.

1434402212101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8589234970.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1434402212101 its reverse (1012122044341), we get a palindrome (2446524256442).

The spelling of 1434402212101 in words is "one trillion, four hundred thirty-four billion, four hundred two million, two hundred twelve thousand, one hundred one".