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1434403001401 = 2362365347887
BaseRepresentation
bin10100110111111001000…
…101001101010000111001
312002010110000022100021221
4110313321011031100321
5142000124132021101
63014542230232041
7205426562224456
oct24677105152071
95063400270257
101434403001401
11503366110457
121b1bb67b5621
13a5357243136
144d5d571082d
15274a35b6aa1
hex14df914d439

1434403001401 has 4 divisors (see below), whose sum is σ = 1496768349312. Its totient is φ = 1372037653492.

The previous prime is 1434403001399. The next prime is 1434403001467. The reversal of 1434403001401 is 1041003044341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1434403001401 - 21 = 1434403001399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1434403001201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31182673921 + ... + 31182673966.

It is an arithmetic number, because the mean of its divisors is an integer number (374192087328).

Almost surely, 21434403001401 is an apocalyptic number.

It is an amenable number.

1434403001401 is a deficient number, since it is larger than the sum of its proper divisors (62365347911).

1434403001401 is an equidigital number, since it uses as much as digits as its factorization.

1434403001401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 62365347910.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1434403001401 its reverse (1041003044341), we get a palindrome (2475406045742).

The spelling of 1434403001401 in words is "one trillion, four hundred thirty-four billion, four hundred three million, one thousand, four hundred one".

Divisors: 1 23 62365347887 1434403001401