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143441114 = 271720557
BaseRepresentation
bin10001000110010…
…11110011011010
3100222220120012212
420203023303122
5243210103424
622122235122
73361141445
oct1043136332
9328816185
10143441114
1173a72483
1240055aa2
13239436cb
141509c65c
15c8d610e
hex88cbcda

143441114 has 4 divisors (see below), whose sum is σ = 215161674. Its totient is φ = 71720556.

The previous prime is 143441107. The next prime is 143441117. The reversal of 143441114 is 411144341.

143441114 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 82210489 + 61230625 = 9067^2 + 7825^2 .

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 143441114.

It is not an unprimeable number, because it can be changed into a prime (143441117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35860277 + ... + 35860280.

Almost surely, 2143441114 is an apocalyptic number.

143441114 is a deficient number, since it is larger than the sum of its proper divisors (71720560).

143441114 is an equidigital number, since it uses as much as digits as its factorization.

143441114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71720559.

The product of its digits is 768, while the sum is 23.

The square root of 143441114 is about 11976.6904443590. The cubic root of 143441114 is about 523.4692998261.

Adding to 143441114 its reverse (411144341), we get a palindrome (554585455).

The spelling of 143441114 in words is "one hundred forty-three million, four hundred forty-one thousand, one hundred fourteen".

Divisors: 1 2 71720557 143441114