Search a number
-
+
1434413321207 is a prime number
BaseRepresentation
bin10100110111111001101…
…100100100101111110111
312002010110201201122101222
4110313321230210233313
5142000134302234312
63014543235340555
7205430046025406
oct24677154445767
95063421648358
101434413321207
11503370a19919
121b1bba15175b
13a5359417429
144d5d6c3963d
15274a4454672
hex14df9b24bf7

1434413321207 has 2 divisors, whose sum is σ = 1434413321208. Its totient is φ = 1434413321206.

The previous prime is 1434413321177. The next prime is 1434413321323. The reversal of 1434413321207 is 7021233144341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1434413321207 - 210 = 1434413320183 is a prime.

It is a super-3 number, since 3×14344133212073 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434413321507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717206660603 + 717206660604.

It is an arithmetic number, because the mean of its divisors is an integer number (717206660604).

Almost surely, 21434413321207 is an apocalyptic number.

1434413321207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434413321207 is an equidigital number, since it uses as much as digits as its factorization.

1434413321207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 35.

Adding to 1434413321207 its reverse (7021233144341), we get a palindrome (8455646465548).

The spelling of 1434413321207 in words is "one trillion, four hundred thirty-four billion, four hundred thirteen million, three hundred twenty-one thousand, two hundred seven".