Base | Representation |
---|---|
bin | 1000010110010111010… |
… | …0100100101110111101 |
3 | 111201020201210211112212 |
4 | 2011211310210232331 |
5 | 4322232200422113 |
6 | 145521344110205 |
7 | 13235426411201 |
oct | 2054564445675 |
9 | 451221724485 |
10 | 143442201533 |
11 | 559194240a4 |
12 | 23972605365 |
13 | 106aca72737 |
14 | 6d2a862b01 |
15 | 3ae80130a8 |
hex | 2165d24bbd |
143442201533 has 2 divisors, whose sum is σ = 143442201534. Its totient is φ = 143442201532.
The previous prime is 143442201523. The next prime is 143442201559. The reversal of 143442201533 is 335102244341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 141859196164 + 1583005369 = 376642^2 + 39787^2 .
It is an emirp because it is prime and its reverse (335102244341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143442201533 - 216 = 143442135997 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 143442201533.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (143442201523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71721100766 + 71721100767.
It is an arithmetic number, because the mean of its divisors is an integer number (71721100767).
Almost surely, 2143442201533 is an apocalyptic number.
It is an amenable number.
143442201533 is a deficient number, since it is larger than the sum of its proper divisors (1).
143442201533 is an equidigital number, since it uses as much as digits as its factorization.
143442201533 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 143442201533 its reverse (335102244341), we get a palindrome (478544445874).
The spelling of 143442201533 in words is "one hundred forty-three billion, four hundred forty-two million, two hundred one thousand, five hundred thirty-three".
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