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14344321309951 is a prime number
BaseRepresentation
bin1101000010111100110000…
…1011010001110011111111
31212210022012102012210211211
43100233030023101303333
53340004132223404301
650301405031425251
73010225440243133
oct320571413216377
955708172183754
1014344321309951
114630435473066
121738038225227
138008821a6039
143783a9a513c3
1519d1de637051
hexd0bcc2d1cff

14344321309951 has 2 divisors, whose sum is σ = 14344321309952. Its totient is φ = 14344321309950.

The previous prime is 14344321309933. The next prime is 14344321310003. The reversal of 14344321309951 is 15990312344341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14344321309951 - 25 = 14344321309919 is a prime.

It is a super-2 number, since 2×143443213099512 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14344321309895 and 14344321309904.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14344321309051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172160654975 + 7172160654976.

It is an arithmetic number, because the mean of its divisors is an integer number (7172160654976).

Almost surely, 214344321309951 is an apocalyptic number.

14344321309951 is a deficient number, since it is larger than the sum of its proper divisors (1).

14344321309951 is an equidigital number, since it uses as much as digits as its factorization.

14344321309951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1399680, while the sum is 49.

The spelling of 14344321309951 in words is "fourteen trillion, three hundred forty-four billion, three hundred twenty-one million, three hundred nine thousand, nine hundred fifty-one".