Base | Representation |
---|---|
bin | 1101000010111100111000… |
… | …1001010010110001001101 |
3 | 1212210022021201101010001121 |
4 | 3100233032021102301031 |
5 | 3340004214203002023 |
6 | 50301412211440541 |
7 | 3010226321106301 |
oct | 320571611226115 |
9 | 55708251333047 |
10 | 14344354344013 |
11 | 4630452086041 |
12 | 17380472b6151 |
13 | 800888ca1015 |
14 | 3783b01add01 |
15 | 19d1e24aed5d |
hex | d0bce252c4d |
14344354344013 has 2 divisors, whose sum is σ = 14344354344014. Its totient is φ = 14344354344012.
The previous prime is 14344354343987. The next prime is 14344354344097. The reversal of 14344354344013 is 31044345344341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13700088057769 + 644266286244 = 3701363^2 + 802662^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14344354344013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14344354342013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172177172006 + 7172177172007.
It is an arithmetic number, because the mean of its divisors is an integer number (7172177172007).
Almost surely, 214344354344013 is an apocalyptic number.
It is an amenable number.
14344354344013 is a deficient number, since it is larger than the sum of its proper divisors (1).
14344354344013 is an equidigital number, since it uses as much as digits as its factorization.
14344354344013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1658880, while the sum is 43.
Adding to 14344354344013 its reverse (31044345344341), we get a palindrome (45388699688354).
The spelling of 14344354344013 in words is "fourteen trillion, three hundred forty-four billion, three hundred fifty-four million, three hundred forty-four thousand, thirteen".
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