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14344354344013 is a prime number
BaseRepresentation
bin1101000010111100111000…
…1001010010110001001101
31212210022021201101010001121
43100233032021102301031
53340004214203002023
650301412211440541
73010226321106301
oct320571611226115
955708251333047
1014344354344013
114630452086041
1217380472b6151
13800888ca1015
143783b01add01
1519d1e24aed5d
hexd0bce252c4d

14344354344013 has 2 divisors, whose sum is σ = 14344354344014. Its totient is φ = 14344354344012.

The previous prime is 14344354343987. The next prime is 14344354344097. The reversal of 14344354344013 is 31044345344341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13700088057769 + 644266286244 = 3701363^2 + 802662^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14344354344013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14344354342013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172177172006 + 7172177172007.

It is an arithmetic number, because the mean of its divisors is an integer number (7172177172007).

Almost surely, 214344354344013 is an apocalyptic number.

It is an amenable number.

14344354344013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14344354344013 is an equidigital number, since it uses as much as digits as its factorization.

14344354344013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1658880, while the sum is 43.

Adding to 14344354344013 its reverse (31044345344341), we get a palindrome (45388699688354).

The spelling of 14344354344013 in words is "fourteen trillion, three hundred forty-four billion, three hundred fifty-four million, three hundred forty-four thousand, thirteen".