Base | Representation |
---|---|
bin | 10100110111111011011… |
… | …101110111110000011011 |
3 | 12002010112210121120022212 |
4 | 110313323131313300123 |
5 | 142000214403140324 |
6 | 3014550220105335 |
7 | 205430556334616 |
oct | 24677335676033 |
9 | 5063483546285 |
10 | 1434443021339 |
11 | 503386764a89 |
12 | 1b200809524b |
13 | a5362615a83 |
14 | 4d5dab6b17d |
15 | 274a6d6e70e |
hex | 14dfb777c1b |
1434443021339 has 2 divisors, whose sum is σ = 1434443021340. Its totient is φ = 1434443021338.
The previous prime is 1434443021317. The next prime is 1434443021393. The reversal of 1434443021339 is 9331203444341.
Together with next prime (1434443021393) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1434443021339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1434443021296 and 1434443021305.
It is not a weakly prime, because it can be changed into another prime (1434443021939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717221510669 + 717221510670.
It is an arithmetic number, because the mean of its divisors is an integer number (717221510670).
Almost surely, 21434443021339 is an apocalyptic number.
1434443021339 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434443021339 is an equidigital number, since it uses as much as digits as its factorization.
1434443021339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 373248, while the sum is 41.
The spelling of 1434443021339 in words is "one trillion, four hundred thirty-four billion, four hundred forty-three million, twenty-one thousand, three hundred thirty-nine".
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