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1434443021317 is a prime number
BaseRepresentation
bin10100110111111011011…
…101110111110000000101
312002010112210121120022001
4110313323131313300011
5142000214403140232
63014550220105301
7205430556334555
oct24677335676005
95063483546261
101434443021317
11503386764a69
121b2008095231
13a5362615a67
144d5dab6b165
15274a6d6e6e7
hex14dfb777c05

1434443021317 has 2 divisors, whose sum is σ = 1434443021318. Its totient is φ = 1434443021316.

The previous prime is 1434443021293. The next prime is 1434443021339. The reversal of 1434443021317 is 7131203444341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1078542483841 + 355900537476 = 1038529^2 + 596574^2 .

It is a cyclic number.

It is not a de Polignac number, because 1434443021317 - 27 = 1434443021189 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1434440021317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717221510658 + 717221510659.

It is an arithmetic number, because the mean of its divisors is an integer number (717221510659).

Almost surely, 21434443021317 is an apocalyptic number.

It is an amenable number.

1434443021317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434443021317 is an equidigital number, since it uses as much as digits as its factorization.

1434443021317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 37.

Adding to 1434443021317 its reverse (7131203444341), we get a palindrome (8565646465658).

The spelling of 1434443021317 in words is "one trillion, four hundred thirty-four billion, four hundred forty-three million, twenty-one thousand, three hundred seventeen".