Base | Representation |
---|---|
bin | 11010101101111111… |
… | …01010110110001011 |
3 | 1101000200120200212121 |
4 | 31112333222312023 |
5 | 213334133324120 |
6 | 10331214552111 |
7 | 1015316445322 |
oct | 152677526613 |
9 | 41020520777 |
10 | 14344433035 |
11 | 60a1070939 |
12 | 2943b08637 |
13 | 1477a961ca |
14 | 9a11350b9 |
15 | 58e4bc5aa |
hex | 356fead8b |
14344433035 has 4 divisors (see below), whose sum is σ = 17213319648. Its totient is φ = 11475546424.
The previous prime is 14344433003. The next prime is 14344433039. The reversal of 14344433035 is 53033444341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14344433035 - 25 = 14344433003 is a prime.
It is a super-2 number, since 2×143444330352 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14344433039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1434443299 + ... + 1434443308.
It is an arithmetic number, because the mean of its divisors is an integer number (4303329912).
Almost surely, 214344433035 is an apocalyptic number.
14344433035 is a deficient number, since it is larger than the sum of its proper divisors (2868886613).
14344433035 is an equidigital number, since it uses as much as digits as its factorization.
14344433035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2868886612.
The product of its (nonzero) digits is 103680, while the sum is 34.
Adding to 14344433035 its reverse (53033444341), we get a palindrome (67377877376).
The spelling of 14344433035 in words is "fourteen billion, three hundred forty-four million, four hundred thirty-three thousand, thirty-five".
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