Base | Representation |
---|---|
bin | 1101000011000000000011… |
… | …0010011111010110011011 |
3 | 1212210101110221011022210022 |
4 | 3100300000302133112123 |
5 | 3340012434211114001 |
6 | 50302032402541055 |
7 | 3010256346103661 |
oct | 320600062372633 |
9 | 55711427138708 |
10 | 14345204004251 |
11 | 463084875538a |
12 | 173824396778b |
13 | 800993020763 |
14 | 378450d84c31 |
15 | 19d241d9611b |
hex | d0c00c9f59b |
14345204004251 has 2 divisors, whose sum is σ = 14345204004252. Its totient is φ = 14345204004250.
The previous prime is 14345204004239. The next prime is 14345204004259. The reversal of 14345204004251 is 15240040254341.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14345204004251 - 214 = 14345203987867 is a prime.
It is not a weakly prime, because it can be changed into another prime (14345204004259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7172602002125 + 7172602002126.
It is an arithmetic number, because the mean of its divisors is an integer number (7172602002126).
Almost surely, 214345204004251 is an apocalyptic number.
14345204004251 is a deficient number, since it is larger than the sum of its proper divisors (1).
14345204004251 is an equidigital number, since it uses as much as digits as its factorization.
14345204004251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 35.
Adding to 14345204004251 its reverse (15240040254341), we get a palindrome (29585244258592).
The spelling of 14345204004251 in words is "fourteen trillion, three hundred forty-five billion, two hundred four million, four thousand, two hundred fifty-one".
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