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14345212441 = 72049316063
BaseRepresentation
bin11010101110000101…
…01001001000011001
31101000202001022000111
431113002221020121
5213334333244231
610331243404321
71015326202540
oct152702511031
941022038014
1014345212441
1160a155347a
1229442236a1
131477ca9bb1
149a1299157
1558e5c34b1
hex3570a9219

14345212441 has 4 divisors (see below), whose sum is σ = 16394528512. Its totient is φ = 12295896372.

The previous prime is 14345212429. The next prime is 14345212451. The reversal of 14345212441 is 14421254341.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14345212441 - 217 = 14345081369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14345212411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1024658025 + ... + 1024658038.

It is an arithmetic number, because the mean of its divisors is an integer number (4098632128).

Almost surely, 214345212441 is an apocalyptic number.

It is an amenable number.

14345212441 is a deficient number, since it is larger than the sum of its proper divisors (2049316071).

14345212441 is an equidigital number, since it uses as much as digits as its factorization.

14345212441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2049316070.

The product of its digits is 15360, while the sum is 31.

Adding to 14345212441 its reverse (14421254341), we get a palindrome (28766466782).

The spelling of 14345212441 in words is "fourteen billion, three hundred forty-five million, two hundred twelve thousand, four hundred forty-one".

Divisors: 1 7 2049316063 14345212441