Base | Representation |
---|---|
bin | 10100111000000111011… |
… | …010001110000100100011 |
3 | 12002011001202122101111100 |
4 | 110320013122032010203 |
5 | 142001122202001010 |
6 | 3015022134445443 |
7 | 205435541421201 |
oct | 24700732160443 |
9 | 5064052571440 |
10 | 1434643390755 |
11 | 50347987a543 |
12 | 1b2063203883 |
13 | a5394c9c263 |
14 | 4d619608071 |
15 | 274b974d2c0 |
hex | 14e0768e123 |
1434643390755 has 48 divisors (see below), whose sum is σ = 2548658661120. Its totient is φ = 746141143104.
The previous prime is 1434643390751. The next prime is 1434643390871. The reversal of 1434643390755 is 5570933464341.
1434643390755 is a `hidden beast` number, since 1 + 43 + 464 + 3 + 3 + 90 + 7 + 55 = 666.
It is a Cunningham number, because it is equal to 11977662-1.
It is not a de Polignac number, because 1434643390755 - 22 = 1434643390751 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1434643390751) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 598882 + ... + 1796648.
It is an arithmetic number, because the mean of its divisors is an integer number (53097055440).
Almost surely, 21434643390755 is an apocalyptic number.
1434643390755 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1434643390755 is a deficient number, since it is larger than the sum of its proper divisors (1114015270365).
1434643390755 is a wasteful number, since it uses less digits than its factorization.
1434643390755 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1198440 (or 1198437 counting only the distinct ones).
The product of its (nonzero) digits is 16329600, while the sum is 54.
The spelling of 1434643390755 in words is "one trillion, four hundred thirty-four billion, six hundred forty-three million, three hundred ninety thousand, seven hundred fifty-five".
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