Base | Representation |
---|---|
bin | 10100111000000111011… |
… | …010001110000110010111 |
3 | 12002011001202122101122122 |
4 | 110320013122032012113 |
5 | 142001122202001441 |
6 | 3015022134450155 |
7 | 205435541421425 |
oct | 24700732160627 |
9 | 5064052571578 |
10 | 1434643390871 |
11 | 50347987a639 |
12 | 1b206320395b |
13 | a5394c9c322 |
14 | 4d619608115 |
15 | 274b974d34b |
hex | 14e0768e197 |
1434643390871 has 2 divisors, whose sum is σ = 1434643390872. Its totient is φ = 1434643390870.
The previous prime is 1434643390751. The next prime is 1434643390963. The reversal of 1434643390871 is 1780933464341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1434643390871 - 214 = 1434643374487 is a prime.
It is a super-2 number, since 2×14346433908712 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1434643890871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717321695435 + 717321695436.
It is an arithmetic number, because the mean of its divisors is an integer number (717321695436).
Almost surely, 21434643390871 is an apocalyptic number.
1434643390871 is a deficient number, since it is larger than the sum of its proper divisors (1).
1434643390871 is an equidigital number, since it uses as much as digits as its factorization.
1434643390871 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5225472, while the sum is 53.
The spelling of 1434643390871 in words is "one trillion, four hundred thirty-four billion, six hundred forty-three million, three hundred ninety thousand, eight hundred seventy-one".
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