14353054040153 has 4 divisors (see below), whose sum is σ = 14366480658660. Its totient is φ = 14339627421648.

The previous prime is 14353054040147. The next prime is 14353054040179. The reversal of 14353054040153 is 35104045035341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3741702185104 + 10611351855049 = 1934348^2 + 3257507^2 .

It is a cyclic number.

It is not a de Polignac number, because 14353054040153 - 2⁴ = 14353054040137 is a prime.

It is a super-2 number, since 2×14353054040153² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14353054030153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6713307650 + ... + 6713309787.

It is an arithmetic number, because the mean of its divisors is an integer number (3591620164665).

Almost surely, 2^{14353054040153} is an apocalyptic number.

It is an amenable number.

14353054040153 is a deficient number, since it is larger than the sum of its proper divisors (13426618507).

14353054040153 is a wasteful number, since it uses less digits than its factorization.

14353054040153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13426618506.

The product of its (nonzero) digits is 216000, while the sum is 38.

Adding to 14353054040153 its reverse (35104045035341), we get a palindrome (49457099075494).

The spelling of 14353054040153 in words is "fourteen trillion, three hundred fifty-three billion, fifty-four million, forty thousand, one hundred fifty-three".