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14353544035 = 52870708807
BaseRepresentation
bin11010101111000100…
…11011001101100011
31101001022201120211001
431113202123031203
5213344001402120
610332142132431
71015460053105
oct152742331543
941038646731
1014353544035
1160a6224096
122946b81117
13147993622c
149a2427575
155901bbe0a
hex35789b363

14353544035 has 4 divisors (see below), whose sum is σ = 17224252848. Its totient is φ = 11482835224.

The previous prime is 14353544021. The next prime is 14353544047. The reversal of 14353544035 is 53044535341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14353544035 - 25 = 14353544003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14353543985 and 14353544003.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1435354399 + ... + 1435354408.

It is an arithmetic number, because the mean of its divisors is an integer number (4306063212).

Almost surely, 214353544035 is an apocalyptic number.

14353544035 is a deficient number, since it is larger than the sum of its proper divisors (2870708813).

14353544035 is an equidigital number, since it uses as much as digits as its factorization.

14353544035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2870708812.

The product of its (nonzero) digits is 216000, while the sum is 37.

The spelling of 14353544035 in words is "fourteen billion, three hundred fifty-three million, five hundred forty-four thousand, thirty-five".

Divisors: 1 5 2870708807 14353544035