Base | Representation |
---|---|
bin | 1101000011100000110110… |
… | …1110111010000100110011 |
3 | 1212211020012201021022202211 |
4 | 3100320031232322010303 |
5 | 3340134003320303124 |
6 | 50310050333352551 |
7 | 3011020530156202 |
oct | 320701556720463 |
9 | 55736181238684 |
10 | 14354011103539 |
11 | 4634558072438 |
12 | 1739aa1338757 |
13 | 801767830c03 |
14 | 378a48905239 |
15 | 19d5aa16be94 |
hex | d0e0dbba133 |
14354011103539 has 2 divisors, whose sum is σ = 14354011103540. Its totient is φ = 14354011103538.
The previous prime is 14354011103521. The next prime is 14354011103623. The reversal of 14354011103539 is 93530111045341.
14354011103539 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14354011103539 - 25 = 14354011103507 is a prime.
It is not a weakly prime, because it can be changed into another prime (14354011103339) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177005551769 + 7177005551770.
It is an arithmetic number, because the mean of its divisors is an integer number (7177005551770).
Almost surely, 214354011103539 is an apocalyptic number.
14354011103539 is a deficient number, since it is larger than the sum of its proper divisors (1).
14354011103539 is an equidigital number, since it uses as much as digits as its factorization.
14354011103539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 14354011103539 in words is "fourteen trillion, three hundred fifty-four billion, eleven million, one hundred three thousand, five hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •