Base | Representation |
---|---|
bin | 1101000011100000110110… |
… | …1110111010000100100001 |
3 | 1212211020012201021022202011 |
4 | 3100320031232322010201 |
5 | 3340134003320303041 |
6 | 50310050333352521 |
7 | 3011020530156145 |
oct | 320701556720441 |
9 | 55736181238664 |
10 | 14354011103521 |
11 | 4634558072421 |
12 | 1739aa1338741 |
13 | 801767830bbb |
14 | 378a48905225 |
15 | 19d5aa16be81 |
hex | d0e0dbba121 |
14354011103521 has 2 divisors, whose sum is σ = 14354011103522. Its totient is φ = 14354011103520.
The previous prime is 14354011103507. The next prime is 14354011103539. The reversal of 14354011103521 is 12530111045341.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13771231543521 + 582779560000 = 3710961^2 + 763400^2 .
It is a cyclic number.
It is not a de Polignac number, because 14354011103521 - 25 = 14354011103489 is a prime.
It is not a weakly prime, because it can be changed into another prime (14354011107521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177005551760 + 7177005551761.
It is an arithmetic number, because the mean of its divisors is an integer number (7177005551761).
Almost surely, 214354011103521 is an apocalyptic number.
It is an amenable number.
14354011103521 is a deficient number, since it is larger than the sum of its proper divisors (1).
14354011103521 is an equidigital number, since it uses as much as digits as its factorization.
14354011103521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 14354011103521 its reverse (12530111045341), we get a palindrome (26884122148862).
The spelling of 14354011103521 in words is "fourteen trillion, three hundred fifty-four billion, eleven million, one hundred three thousand, five hundred twenty-one".
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