Base | Representation |
---|---|
bin | 11010101111001000… |
… | …10111010000101111 |
3 | 1101001100200101210212 |
4 | 31113210113100233 |
5 | 213344114132033 |
6 | 10332201053035 |
7 | 1015464300344 |
oct | 152744272057 |
9 | 41040611725 |
10 | 14354052143 |
11 | 60a6540912 |
12 | 294718717b |
13 | 1479a835a2 |
14 | 9a251a7cb |
15 | 59026c748 |
hex | 35791742f |
14354052143 has 4 divisors (see below), whose sum is σ = 14502032160. Its totient is φ = 14206072128.
The previous prime is 14354052137. The next prime is 14354052161. The reversal of 14354052143 is 34125045341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14354052143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14354052103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73989863 + ... + 73990056.
It is an arithmetic number, because the mean of its divisors is an integer number (3625508040).
Almost surely, 214354052143 is an apocalyptic number.
14354052143 is a deficient number, since it is larger than the sum of its proper divisors (147980017).
14354052143 is an equidigital number, since it uses as much as digits as its factorization.
14354052143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 147980016.
The product of its (nonzero) digits is 28800, while the sum is 32.
Adding to 14354052143 its reverse (34125045341), we get a palindrome (48479097484).
The spelling of 14354052143 in words is "fourteen billion, three hundred fifty-four million, fifty-two thousand, one hundred forty-three".
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