14354120441103 has 4 divisors (see below), whose sum is σ = 19138827254808. Its totient is φ = 9569413627400.

The previous prime is 14354120441071. The next prime is 14354120441113. The reversal of 14354120441103 is 30114402145341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14354120441103 - 2⁵ = 14354120441071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14354120441113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2392353406848 + ... + 2392353406853.

It is an arithmetic number, because the mean of its divisors is an integer number (4784706813702).

Almost surely, 2^{14354120441103} is an apocalyptic number.

14354120441103 is a deficient number, since it is larger than the sum of its proper divisors (4784706813705).

14354120441103 is an equidigital number, since it uses as much as digits as its factorization.

14354120441103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4784706813704.

The product of its (nonzero) digits is 23040, while the sum is 33.

Adding to 14354120441103 its reverse (30114402145341), we get a palindrome (44468522586444).

The spelling of 14354120441103 in words is "fourteen trillion, three hundred fifty-four billion, one hundred twenty million, four hundred forty-one thousand, one hundred three".