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14354124354001 is a prime number
BaseRepresentation
bin1101000011100001010001…
…1110111011000111010001
31212211020111121101001012101
43100320110132323013101
53340134221313312001
650310105501000401
73011023403606365
oct320702436730721
955736447331171
1014354124354001
114634605a94163
121739b13253101
13801785133913
14378a599852a5
1519d5b508ca01
hexd0e147bb1d1

14354124354001 has 2 divisors, whose sum is σ = 14354124354002. Its totient is φ = 14354124354000.

The previous prime is 14354124353969. The next prime is 14354124354029. The reversal of 14354124354001 is 10045342145341.

It is a happy number.

14354124354001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13256189219025 + 1097935134976 = 3640905^2 + 1047824^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354124354001 - 25 = 14354124353969 is a prime.

It is not a weakly prime, because it can be changed into another prime (14354124354701) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177062177000 + 7177062177001.

It is an arithmetic number, because the mean of its divisors is an integer number (7177062177001).

Almost surely, 214354124354001 is an apocalyptic number.

It is an amenable number.

14354124354001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354124354001 is an equidigital number, since it uses as much as digits as its factorization.

14354124354001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 14354124354001 its reverse (10045342145341), we get a palindrome (24399466499342).

The spelling of 14354124354001 in words is "fourteen trillion, three hundred fifty-four billion, one hundred twenty-four million, three hundred fifty-four thousand, one".