Base | Representation |
---|---|
bin | 1101000011100001101011… |
… | …1110001101110001011111 |
3 | 1212211020210012020000112111 |
4 | 3100320122332031301133 |
5 | 3340134432201021231 |
6 | 50310124350214451 |
7 | 3011026165136464 |
oct | 320703276156137 |
9 | 55736705200474 |
10 | 14354233220191 |
11 | 4634661490a17 |
12 | 1739b437b4427 |
13 | 8017a185cb97 |
14 | 378a6a20366b |
15 | 19d5be8e44b1 |
hex | d0e1af8dc5f |
14354233220191 has 2 divisors, whose sum is σ = 14354233220192. Its totient is φ = 14354233220190.
The previous prime is 14354233220099. The next prime is 14354233220203. The reversal of 14354233220191 is 19102233245341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14354233220191 is a prime.
It is a super-2 number, since 2×143542332201912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14354833220191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177116610095 + 7177116610096.
It is an arithmetic number, because the mean of its divisors is an integer number (7177116610096).
Almost surely, 214354233220191 is an apocalyptic number.
14354233220191 is a deficient number, since it is larger than the sum of its proper divisors (1).
14354233220191 is an equidigital number, since it uses as much as digits as its factorization.
14354233220191 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 14354233220191 in words is "fourteen trillion, three hundred fifty-four billion, two hundred thirty-three million, two hundred twenty thousand, one hundred ninety-one".
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