14354233312453 has 4 divisors (see below), whose sum is σ = 14625067903308. Its totient is φ = 14083398721600.

The previous prime is 14354233312421. The next prime is 14354233312457. The reversal of 14354233312453 is 35421333245341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3890606341444 + 10463626971009 = 1972462^2 + 3234753^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354233312453 - 2⁵ = 14354233312421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14354233312457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135417295348 + ... + 135417295453.

It is an arithmetic number, because the mean of its divisors is an integer number (3656266975827).

Almost surely, 2^{14354233312453} is an apocalyptic number.

It is an amenable number.

14354233312453 is a deficient number, since it is larger than the sum of its proper divisors (270834590855).

14354233312453 is an equidigital number, since it uses as much as digits as its factorization.

14354233312453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 270834590854.

The product of its digits is 1555200, while the sum is 43.

Adding to 14354233312453 its reverse (35421333245341), we get a palindrome (49775566557794).

The spelling of 14354233312453 in words is "fourteen trillion, three hundred fifty-four billion, two hundred thirty-three million, three hundred twelve thousand, four hundred fifty-three".