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14354242031111 = 49129234708821
BaseRepresentation
bin1101000011100001101101…
…1111110100111000000111
31212211020210210210122211212
43100320123133310320013
53340134441424443421
650310125303122035
73011026333054343
oct320703337647007
955736723718755
1014354242031111
114634666459774
121739b4674331b
138017a3626448
14378a6b458623
1519d5c0584e5b
hexd0e1b7f4e07

14354242031111 has 4 divisors (see below), whose sum is σ = 14383476740424. Its totient is φ = 14325007321800.

The previous prime is 14354242031047. The next prime is 14354242031131. The reversal of 14354242031111 is 11113024245341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14354242031111 - 26 = 14354242031047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14354242031131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14617353920 + ... + 14617354901.

It is an arithmetic number, because the mean of its divisors is an integer number (3595869185106).

Almost surely, 214354242031111 is an apocalyptic number.

14354242031111 is a deficient number, since it is larger than the sum of its proper divisors (29234709313).

14354242031111 is an equidigital number, since it uses as much as digits as its factorization.

14354242031111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29234709312.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 14354242031111 its reverse (11113024245341), we get a palindrome (25467266276452).

The spelling of 14354242031111 in words is "fourteen trillion, three hundred fifty-four billion, two hundred forty-two million, thirty-one thousand, one hundred eleven".

Divisors: 1 491 29234708821 14354242031111