Base | Representation |
---|---|
bin | 1101000011100001111110… |
… | …0111110001001100010111 |
3 | 1212211020222121222220221211 |
4 | 3100320133213301030113 |
5 | 3340140112133101124 |
6 | 50310140214122251 |
7 | 3011031133141225 |
oct | 320703747611427 |
9 | 55736877886854 |
10 | 14354311222039 |
11 | 46346a1517958 |
12 | 1739b65950387 |
13 | 8017b4a70919 |
14 | 378a76709b15 |
15 | 19d5c66a0e94 |
hex | d0e1f9f1317 |
14354311222039 has 2 divisors, whose sum is σ = 14354311222040. Its totient is φ = 14354311222038.
The previous prime is 14354311222007. The next prime is 14354311222057. The reversal of 14354311222039 is 93022211345341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14354311222039 - 25 = 14354311222007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14354311221992 and 14354311222010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14354317222039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177155611019 + 7177155611020.
It is an arithmetic number, because the mean of its divisors is an integer number (7177155611020).
Almost surely, 214354311222039 is an apocalyptic number.
14354311222039 is a deficient number, since it is larger than the sum of its proper divisors (1).
14354311222039 is an equidigital number, since it uses as much as digits as its factorization.
14354311222039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 14354311222039 in words is "fourteen trillion, three hundred fifty-four billion, three hundred eleven million, two hundred twenty-two thousand, thirty-nine".
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