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14354702689 is a prime number
BaseRepresentation
bin11010101111001101…
…10110000101100001
31101001101220110012011
431113212312011201
5213344300441224
610332223032521
71015502650105
oct152746660541
941041813164
1014354702689
1160a6945658
12294743b741
131479c50722
149a2649905
1559034a394
hex3579b6161

14354702689 has 2 divisors, whose sum is σ = 14354702690. Its totient is φ = 14354702688.

The previous prime is 14354702651. The next prime is 14354702717. The reversal of 14354702689 is 98620745341.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13395747600 + 958955089 = 115740^2 + 30967^2 .

It is a cyclic number.

It is not a de Polignac number, because 14354702689 - 211 = 14354700641 is a prime.

It is a super-3 number, since 3×143547026893 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (14354702389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7177351344 + 7177351345.

It is an arithmetic number, because the mean of its divisors is an integer number (7177351345).

It is a 1-persistent number, because it is pandigital, but 2⋅14354702689 = 28709405378 is not.

Almost surely, 214354702689 is an apocalyptic number.

It is an amenable number.

14354702689 is a deficient number, since it is larger than the sum of its proper divisors (1).

14354702689 is an equidigital number, since it uses as much as digits as its factorization.

14354702689 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 49.

The spelling of 14354702689 in words is "fourteen billion, three hundred fifty-four million, seven hundred two thousand, six hundred eighty-nine".