Base | Representation |
---|---|
bin | 11010101111010011… |
… | …00001001100011111 |
3 | 1101001110020001121000 |
4 | 31113221201030133 |
5 | 213344440403201 |
6 | 10332250041343 |
7 | 1015511626326 |
oct | 152751411437 |
9 | 41043201530 |
10 | 14355403551 |
11 | 60a7284185 |
12 | 2947719253 |
13 | 147a137738 |
14 | 9a278d0bd |
15 | 590437d86 |
hex | 357a6131f |
14355403551 has 32 divisors (see below), whose sum is σ = 22803379200. Its totient is φ = 8893272960.
The previous prime is 14355403537. The next prime is 14355403553. The reversal of 14355403551 is 15530455341.
14355403551 is a `hidden beast` number, since 1 + 4 + 35 + 540 + 35 + 51 = 666.
It is not a de Polignac number, because 14355403551 - 25 = 14355403519 is a prime.
It is a super-2 number, since 2×143554035512 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14355403553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 161685 + ... + 234206.
It is an arithmetic number, because the mean of its divisors is an integer number (712605600).
Almost surely, 214355403551 is an apocalyptic number.
14355403551 is a deficient number, since it is larger than the sum of its proper divisors (8447975649).
14355403551 is a wasteful number, since it uses less digits than its factorization.
14355403551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 395996 (or 395990 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
Adding to 14355403551 its reverse (15530455341), we get a palindrome (29885858892).
The spelling of 14355403551 in words is "fourteen billion, three hundred fifty-five million, four hundred three thousand, five hundred fifty-one".
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