143630316656551 has 4 divisors (see below), whose sum is σ = 143630341059600. Its totient is φ = 143630292253504.

The previous prime is 143630316656543. The next prime is 143630316656557. The reversal of 143630316656551 is 155656613036341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 143630316656551 - 2³ = 143630316656543 is a prime.

It is a super-2 number, since 2×143630316656551² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143630316656492 and 143630316656501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143630316656557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2664855 + ... + 17156983.

It is an arithmetic number, because the mean of its divisors is an integer number (35907585264900).

Almost surely, 2^{143630316656551} is an apocalyptic number.

143630316656551 is a deficient number, since it is larger than the sum of its proper divisors (24403049).

143630316656551 is an equidigital number, since it uses as much as digits as its factorization.

143630316656551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24403048.

The product of its (nonzero) digits is 17496000, while the sum is 55.

The spelling of 143630316656551 in words is "one hundred forty-three trillion, six hundred thirty billion, three hundred sixteen million, six hundred fifty-six thousand, five hundred fifty-one".