Base | Representation |
---|---|
bin | 100000101010001111001110… |
… | …010010011110111110110011 |
3 | 200211120212002012201002000210 |
4 | 200222033032102132332303 |
5 | 122311344311332411430 |
6 | 1225255155023115203 |
7 | 42153436253534205 |
oct | 4052171622367663 |
9 | 624525065632023 |
10 | 143640052232115 |
11 | 4184a44988429a |
12 | 1413a4a2a42b03 |
13 | 621c277a0a71a |
14 | 2768303950775 |
15 | 1191619e512b0 |
hex | 82a3ce49efb3 |
143640052232115 has 8 divisors (see below), whose sum is σ = 229824083571408. Its totient is φ = 76608027857120.
The previous prime is 143640052232051. The next prime is 143640052232129. The reversal of 143640052232115 is 511232250046341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 143640052232115 - 26 = 143640052232051 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4788001741056 + ... + 4788001741085.
It is an arithmetic number, because the mean of its divisors is an integer number (28728010446426).
Almost surely, 2143640052232115 is an apocalyptic number.
143640052232115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
143640052232115 is a deficient number, since it is larger than the sum of its proper divisors (86184031339293).
143640052232115 is an equidigital number, since it uses as much as digits as its factorization.
143640052232115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9576003482149.
The product of its (nonzero) digits is 172800, while the sum is 39.
The spelling of 143640052232115 in words is "one hundred forty-three trillion, six hundred forty billion, fifty-two million, two hundred thirty-two thousand, one hundred fifteen".
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