Base | Representation |
---|---|
bin | 11010110000111010… |
… | …00001101110100011 |
3 | 1101002101122001200011 |
4 | 31120131001232203 |
5 | 213411414444042 |
6 | 10333451305351 |
7 | 1016034454441 |
oct | 153035015643 |
9 | 41071561604 |
10 | 14368906147 |
11 | 6103966952 |
12 | 295014b257 |
13 | 147cb8463b |
14 | 9a44a5b91 |
15 | 591703a17 |
hex | 358741ba3 |
14368906147 has 2 divisors, whose sum is σ = 14368906148. Its totient is φ = 14368906146.
The previous prime is 14368906063. The next prime is 14368906151. The reversal of 14368906147 is 74160986341.
14368906147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14368906147 is a prime.
It is a super-2 number, since 2×143689061472 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14368906147.
It is not a weakly prime, because it can be changed into another prime (14368906247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7184453073 + 7184453074.
It is an arithmetic number, because the mean of its divisors is an integer number (7184453074).
Almost surely, 214368906147 is an apocalyptic number.
14368906147 is a deficient number, since it is larger than the sum of its proper divisors (1).
14368906147 is an equidigital number, since it uses as much as digits as its factorization.
14368906147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 870912, while the sum is 49.
The spelling of 14368906147 in words is "fourteen billion, three hundred sixty-eight million, nine hundred six thousand, one hundred forty-seven".
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