Search a number
-
+
143802011137 is a prime number
BaseRepresentation
bin1000010111101101000…
…1001000111000000001
3111202011210212001112111
42011323101020320001
54324001303324022
6150021200055321
713250355632611
oct2057321107001
9452153761474
10143802011137
1155a93539404
1223a53004541
1310739481925
146d62564a41
153b198d8477
hex217b448e01

143802011137 has 2 divisors, whose sum is σ = 143802011138. Its totient is φ = 143802011136.

The previous prime is 143802011083. The next prime is 143802011147. The reversal of 143802011137 is 731110208341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 139998698896 + 3803312241 = 374164^2 + 61671^2 .

It is a cyclic number.

It is not a de Polignac number, because 143802011137 - 219 = 143801486849 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143802011099 and 143802011108.

It is not a weakly prime, because it can be changed into another prime (143802011147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71901005568 + 71901005569.

It is an arithmetic number, because the mean of its divisors is an integer number (71901005569).

Almost surely, 2143802011137 is an apocalyptic number.

It is an amenable number.

143802011137 is a deficient number, since it is larger than the sum of its proper divisors (1).

143802011137 is an equidigital number, since it uses as much as digits as its factorization.

143802011137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 143802011137 its reverse (731110208341), we get a palindrome (874912219478).

The spelling of 143802011137 in words is "one hundred forty-three billion, eight hundred two million, eleven thousand, one hundred thirty-seven".