Base | Representation |
---|---|
bin | 1000010111101101000… |
… | …1001000111000001011 |
3 | 111202011210212001112212 |
4 | 2011323101020320023 |
5 | 4324001303324042 |
6 | 150021200055335 |
7 | 13250355632624 |
oct | 2057321107013 |
9 | 452153761485 |
10 | 143802011147 |
11 | 55a93539413 |
12 | 23a5300454b |
13 | 10739481932 |
14 | 6d62564a4b |
15 | 3b198d8482 |
hex | 217b448e0b |
143802011147 has 2 divisors, whose sum is σ = 143802011148. Its totient is φ = 143802011146.
The previous prime is 143802011137. The next prime is 143802011149. The reversal of 143802011147 is 741110208341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143802011147 - 26 = 143802011083 is a prime.
Together with 143802011149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (143802011149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71901005573 + 71901005574.
It is an arithmetic number, because the mean of its divisors is an integer number (71901005574).
Almost surely, 2143802011147 is an apocalyptic number.
143802011147 is a deficient number, since it is larger than the sum of its proper divisors (1).
143802011147 is an equidigital number, since it uses as much as digits as its factorization.
143802011147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5376, while the sum is 32.
Adding to 143802011147 its reverse (741110208341), we get a palindrome (884912219488).
The spelling of 143802011147 in words is "one hundred forty-three billion, eight hundred two million, eleven thousand, one hundred forty-seven".
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