Base | Representation |
---|---|
bin | 10100111011100001011… |
… | …101000011111010011111 |
3 | 12002111111201011002012022 |
4 | 110323201131003322133 |
5 | 142031120200144141 |
6 | 3020425134130355 |
7 | 205625311421012 |
oct | 24734135037237 |
9 | 5074451132168 |
10 | 1438301568671 |
11 | 504a86814780 |
12 | 1b29043509bb |
13 | a5828b3bb86 |
14 | 4d8853bd379 |
15 | 276309a2b4b |
hex | 14ee1743e9f |
1438301568671 has 16 divisors (see below), whose sum is σ = 1573806948480. Its totient is φ = 1303589074080.
The previous prime is 1438301568647. The next prime is 1438301568679. The reversal of 1438301568671 is 1768651038341.
It is a cyclic number.
It is not a de Polignac number, because 1438301568671 - 218 = 1438301306527 is a prime.
It is a super-2 number, since 2×14383015686712 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1438301568679) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30737825 + ... + 30784581.
It is an arithmetic number, because the mean of its divisors is an integer number (98362934280).
Almost surely, 21438301568671 is an apocalyptic number.
1438301568671 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1438301568671 is a deficient number, since it is larger than the sum of its proper divisors (135505379809).
1438301568671 is a wasteful number, since it uses less digits than its factorization.
1438301568671 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55174.
The product of its (nonzero) digits is 2903040, while the sum is 53.
The spelling of 1438301568671 in words is "one trillion, four hundred thirty-eight billion, three hundred one million, five hundred sixty-eight thousand, six hundred seventy-one".
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